Select the correct statement regarding $B_{2} H_{6}$ .

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

It has only $2 c - 2 e^{-}$ bond

It is planar

It does not react with ${NH}_{3}$

Hybridisation of boron is $s p^{3}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Boron contains three valence electrons, thus when it undergoes hybridization, it should form three bonds in a molecule ( ${sp}^{2}$ ) since only the s and p orbitals are utilised, and the final p orbital is left empty.

However, the diborane, $B_{2} H_{6}$ , has three centred bonds and two electrons per bond. Four hydrogen atoms form a connection with each boron atom. Tetrahedral geometry results from this.

Thus, each boron atom has undergone ${sp}^{3}$ hybridization.

Watch 3-min video & get full concept clarity