Select the correct statement(s) among the following:

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$O - O$ bond length in $H_{2} O_{2} and O_{2} F_{2}$ is same, since both have similar open book structure.

$S F_{4}$ can act as Lewis acid with $C s F$ but act as Lewis base with $B F_{3}$

S–S bond length in $S_{2} F_{2}$ and $S_{2} C l_{2} .$ are nearly equal as they are isostructural but $S - S$ bond length is a little more in $S_{2} C l_{2} .$

$S - S$ bond lengths in $S_{8}$ and $H_{2} S_{2}$ are nearly equal

answer is A, C, D.

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Detailed Solution

A) $S F_{4}$ can act both as $F^{-}$ donor or acceptor. Its behaviour depends on its reaction partner. $B F_{3}$ is stronger Lewis acid than $S F_{4},$ so with $B F_{3}$ it acts as Lewis base while reacting with $C s F$ it acts as Lewis acid as $C s F$ ionizes giving $F^{-}$ ion.
B) $O_{2} F_{2}$ has double bond character between oxygen atoms due to resonance
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So $O - O$ bond length in $O_{2} F_{2}$ is less than in $H_{2} O_{2}$ since in $H_{2} O_{2}$ such resonance is not present.
C) In $S_{8}$ and $H_{2} S_{2}, S - S$ bond lengths are same $206 p m$ as there is no difference in electro negativities of sulphur and hydrogen
D) In both $S_{2} F_{2} (189 p m) S_{2} C l_{2} (193 p m)$ the $S - S$ bond lengths are nearly equal but due to less electronegativity of chlorine $S - S$ bond length is a little more in $S_{2} C l_{2}$