Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Select the correct statement(s) :

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Clay and lime on strong heating produces a fused mass known as 'cement clinkers'

b

Melting point and boiling point of II A group elements are higher than that of corresponding I A group elements

c

Zeolite method is used to remove permanent hardness of water

d

'Ba' is soluble in both water and liquid NH3

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The product of heating limestone (calcium carbonate) and clay is hydraulic mortar.
Group 2 metals have stronger metallic bonds, which leads to greater cohesive energies and compact atom packing. This explains why group 2 metals are harder and have higher melting and boiling temperatures than group 1 metals.
As the calcium and magnesium ions are removed from the water and sodium permutate is changed into calcium and magnesium permutate, hard water becomes soft as a result of the calcium and magnesium ions being trapped in zeolite.
Ba is a kind of metal that, like ammonia, may dissolve in water.

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring