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The value of $Q_{C}$ for a given reaction is constant.

A change in the physical state of gaseous product shows a change in the value of equilibrium constant of that reaction.

The value of ratio of $\frac{Q_{C}}{K_{C}}$ can be used to predict the direction in which a system will proceed spontaneously towards equilibrium.

The rate constants for forward and backward reaction for reversible reaction always increases with temperature but their ratio $(i . e, \frac{K_{f}}{K_{b}})$ may increase or decrease with temperature.

answer is B, C, D.

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Detailed Solution

Q changes with time, $\frac{Q}{K}$ gives direction of reaction. $K_{f}$ and $K_{b}$ increases with temperature.

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