Select the correct statement(s) about the compound NO[BF₄]

Total $\sigma -$ bonds = 5 - Diamagnetic
Total $\mathrm{\pi }-$ bonds = 2- Bond order of NO⁺ is 3 > NO

B−F bonds are longer in ${\mathrm{BF}}_4^{-}$​ than in BF₃​ due to absence of pπ−pπ back bonding in ${\mathrm{BF}}_4^{-}$.