Select the correct statement(s) regarding compounds of noble gases :

According to the following equation,  $\mathrm{Kr}+{\mathrm{F}}_2\to \mathrm{KrF}$ when fluorine gas and krypton gas interact under extremely forceful conditions, ${\mathrm{Krf}}_2$ is formed.

$\left({\mathrm{RNF}}_2\right)$ has a conserved RING finger domain at its N-terminus. RNF₂ represses a variety of genes involved in cell cycle, development, differentiation, and malignant transformation as a member of the Polycomb group family of proteins.

Since He and Ne are tiny, they have very high ionisation energies, which prevents their electrons from being stimulated to higher energy levels. From He to Rn, the group's ionisation energies decreases. It gets simpler to remove electrons as the size increases. These factors prevent the existence of molecules containing He and Ne.

$\begin{array}{l}\mathrm{Xe}\left(\mathrm{g}\right)+{\mathrm{F}}_2\left(\mathrm{g}\right)\stackrel{673\mathrm{K}}{\overrightarrow{\mathrm{lbar}}}{\mathrm{XeF}}_2\\ \mathrm{Xe}\left(\mathrm{g}\right)+2{\mathrm{F}}_2\left(\mathrm{g}\right)\underset{7\mathrm{bar}}{\stackrel{873\mathrm{K}}{⟶}}{\mathrm{XeF}}_4\\ \mathrm{Xe}\left(\mathrm{g}\right)+3{\mathrm{F}}_2\left(\mathrm{g}\right)\underset{60-70\mathrm{bar}}{\stackrel{573\mathrm{K}}{⟶}}{\mathrm{XeF}}_6\left(\mathrm{s}\right)\end{array}$

Hence all the given options are correct.