Select the incorrect order for given properties :

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Thermal stability : ${BaSO}_{4} > {SrSO}_{4} > {CaSO}_{4}$

Solubility: ${BaSO}_{4} > {SrSO}_{4} > {CaSO}_{4}$

Thermal stability: ${Li}_{2} {CO}_{3} < {Na}_{2} {CO}_{3} < K_{2} {CO}_{3}$

Solubility : ${Li}_{2} {CO}_{3} > {Na}_{2} {CO}_{3} > K_{2} {CO}_{3}$

answer is B, D.

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Detailed Solution

The correct order of thermal stability is, ⁣ ${BaSO}_{4} > {SrSO}_{4} > {CaSO}_{4}$

Due to low polarizability and a significant overlap of hybrid orbitals between species with similar sizes, the thermal stability of metal ions rises as their size increases.

The correct order of thermal stability is, ⁣ ${Li}_{2} {CO}_{3} < {Na}_{2} {CO}_{3} < K_{2} {CO}_{3}$

Due to its covalent structure, lithium carbonate is not heat stable. Carbonate ions are much larger than lithium ions, which are much smaller. As a result, the massive carbonate ions are polarized by the tiny lithium-ion, creating more stable lithium oxide.

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