Q.

Set - ASet - B
A) 1 mole gas occupies volume at STP1) CaO, CO2
B) 2 moles of gas occupies volume at STP   2) 22.42 Lit
C) Stoichiometric equation3) H2(g)+12O2(g)H2O (l)
D) The products of decomposition of the 4) 44.84 Lit

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a

A - 4, B - 3, C - 2, D - 1

b

A - 4, B - 1, C - 2, D - 3

c

A - 2, B -  4, C - 3, D - 1

d

A - 1, B - 2, C - 3, D - 4

answer is D.

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Detailed Solution

The balanced chemical equation for the decomposition of CaCO3 is as given below.

CaCO3(s)CaO (s)+ CO2(g)

At STP, one mole of any gas occupies 22.42 L .So, 2 moles of gas at STP occupies 44.84 L.

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Set - ASet - BA) 1 mole gas occupies volume at STP1) CaO, CO2B) 2 moles of gas occupies volume at STP   2) 22.42 LitC) Stoichiometric equation3) H2(g)+12O2(g)→H2O (l)D) The products of decomposition of the 4) 44.84 Lit