Set A has 3 elements. Set B has 4 elements. The number of surjections that can be defined from A to B is

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answer is C.

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Detailed Solution

Given that set $A$ has three elements and the set $B$ has four elements

If the number of elements of codomain set is more than the number of elements of the domian set then number of surjections from the set $A$ to the set $B$ is zero

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