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Q.

Set A has 3 elements. Set B has 4 elements. The number of surjections that can be defined from A to B is

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a

12

b

64

c

0

d

144

answer is C.

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Detailed Solution

Given that set A has three elements and the set B has four elements

If the number of elements of codomain set is more than the number of elements of the domian set then number of surjections from the set A  to the set  B is zero

 

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