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Set the drifts suffered by boat in increasing order.
a) d = 1000 m V_R = 2 m/s V_b = 4 m/s
b) d = 500 m V_R = 1 m/s V_b = 6 m/s
c) d = 1000 m V_R = 6 m/s V_b = 6 m/s
( d → width of river V_R → velocity of river V_b → velocity of Boat). The boat moves perpendicular to width of the river.

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a, b, c

b, c, a

b, a, c

c, b, a

answer is C.

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Detailed Solution

$Drift = \frac{width}{boat speed} \times river speed$

$d_{a} = \frac{1000}{4} \times 2 = \frac{1000}{2} m$

$d_{b} = \frac{1000}{6} \times 1 = \frac{1000}{6} m$

$d_{c} = \frac{1000}{6} \times 6 = \frac{1000}{1} m$

$d_{b} < d_{a} < d_{c}$

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