Seven capacitors are connected as shown in the figure.
 

The equivalent capacitance in $\mathrm{\mu }$F between A and B is

The p.d. across the 8$\mathrm{\mu }$F capacitor is zero  as the circuit is balanced wheatstone bridge .
$\mathrm{C}=2\times \frac{5\times 3}{5+3}=3.75\mathrm{\mu F}\mathrm{C}=\frac{10\times 6}{10+6}=3.75\mathrm{\mu F}$