Seven capacitors each of capacity  $2\mu F$ are to be so connected to have a total capacity $\frac{10}{11}\mu F$ . Which will be the necessary figure as shown

Let say each capacitor has C capacitance.

There are five parallel capacitors and their equivalent capacitance is 5C

and other two are in series with this combination C/2.

Finally equivalent capacitance  of 5C and C/2 which are in series is $C_{eq}=\frac{C_1{C}_2}{C_1+C_2}=5C\times \left(C/2\right)/\left(5C+C/2\right)=5C/11$ , 

given $C=2\mu F$  then  $C_{eq}=\frac{5\left(2\right)}{11}=\frac{10}{11}\mu F$.