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Seven women and seven men are to sit round a circular table such that there is a man on either side of every women; the number of seating arrangements, is

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${(7!)}^{2}$

${(6!)}^{2}$

$6! x 7!$

$7!$

answer is C.

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Detailed Solution

7 women can sit on a round table in $(7 - 1)! = 6!$

ways. Now, seven places are created which can be filled by 7

men in 7! ways.

Hence, required number of ways = $6! x 7!$ .

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