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Several spherical drops of radius r of a liquid of surface tension T coalesce to form a single drop of radius R and volume V. The energy released in the process is $nVT [\frac{1}{r} - \frac{1}{R}]$ , where n=___________

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answer is 3.

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Detailed Solution

$N \times \frac{4}{3} {πr}^{3} = \frac{4}{3} {πR}^{3} \Rightarrow N = {(\frac{R}{r})}^{3} Surface energy released, E = TΔA = T [N \times 4 {πr}^{2} - 4 {πR}^{2}] = 3 TV [\frac{1}{r} - \frac{1}{R}]$

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