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Q.

${SF}_{2}, {SF}_{4} and {SF}_{6} have the hybridisation at sulphur atom$ $molecule (X = S, Xe, C) ?$

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a

$s p^{2}, s p^{3}, s p^{2} d^{2}$

b

$s p^{3}, s p^{3}, s p^{3} d^{2}$

c

$s p^{3}, s p^{3} d, s p^{3} d^{2}$

d

$s p^{3}, s p d^{2}, d^{2} s p^{3}$

answer is C.

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Detailed Solution

Hybridisation:

$: \overset{Â¨}{S} F_{2} â \frac{1}{2} (6 + 2) = 4 = s p^{3}$
$: {SF}_{4} â \frac{1}{2} (6 + 4) = 5 = s p^{3} d$
${SF}_{6} â \frac{1}{2} (6 + 6) = 6 = s p^{3} d^{2}$

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