Shape and hybridization of IF₅ respectively are

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see-saw, sp³d

pentagonal pyramidal, sp³d³

trigonal bipyramidal, sp³d

square pyramidal, sp³d²

answer is C.

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Detailed Solution

The hybridization of IF₅can be determined by the number of lone pairs around iodine and the number of sigma bonds formed between I and F.

Since the central atom iodine has 7 valence electrons out of which 5 electrons form 5 sigma bonds with F atoms and 2 electrons form 1 lone pair making the stearic number 6 which implies the hybridization of the central atom is sp3d2 where the geometry is octahedral and the shape is square pyramidal.

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