Shape of string transmitting wave along x-axis at some instant is shown. Velocity of point P is  $v=4\pi$ cm/s and  $\theta ={\tan }^{-1}\left(0.004\pi \right)$

$\begin{array}{l}\mathrm{Wave} \mathrm{length} \mathrm{of} \mathrm{the} \mathrm{wave}, \lambda =1\mathrm{m} \\ maximum particle velocity, V_{max}=A\omega =4\pi \\ \therefore wave velocity, v=\frac{\mathrm{\partial }y/\mathrm{\partial }t}{\mathrm{\partial }y/\mathrm{\partial }x}=\frac{4\pi \times {10}^{-2}}{\tan \theta }=\frac{4\pi \times {10}^{-2}}{4\pi \times {10}^{-3}}=10\mathrm{m}/\mathrm{s} \left(\because \mathrm{wave} \mathrm{velocity}=\frac{\mathrm{particle} \mathrm{velocity}}{\mathrm{slope} \mathrm{of} \mathrm{the} \mathrm{wave} }\right)\\ \mathrm{also} \mathrm{frequency}, f or \vartheta =\frac{V}{\lambda }=\frac{V}{1}=10\mathrm{Hz}\\ V_{max}=A\omega \\ 4\pi \times {10}^{-2}=A2\pi \left(10\right)\\ Amplitude of the wave\\ A=2\times {10}^{-3}\mathrm{m}\\ \end{array}$

$\text{ and maximum accelertion of the particle }{a}_{max}=A{\omega }^2=80{\pi }^2\mathrm{cm}/{\sec }^2$