Shape of ${\mathrm{SO}}_2$ molecule is------ and the bond angle in it is--------            

${\mathrm{SO}}_2$(2BP+1LP) ; ${\mathrm{sp}}^2$hybridized, angular shape;

Hints;

Ox.state of Sulphur = Total bonds = 4

Attached atoms to central atom = $\mathrm{\sigma }$ bonds = 2

$\therefore \mathrm{\pi }$ bonds = (4-2) = 2

Due to LP-BP repulsions bond angle slightly decreases;

Instead ${120}^0$ it will be about $119.{30}^0$