Shape Bond angle
A) Tetrahedral 1) $180 °$
B) Linear 2) $120 °$
C) Octahedral 3) $109 ° 28^{1}$
D) Trigonal Planar 4) $90 °$

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A - 3, B - 1, C - 2, D - 4

A - 3, B - 1, C - 4, D - 2

A - 3, B - 2, C - 1, D - 4

A - 3, B - 4, C - 1, D - 2

answer is B.

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Detailed Solution

In tetrahedral molecule, the central atom undergoes ${sp}^{3}$ hybridization. So the bond angle is $109 ° 28^{1}$ .

In linear molecule, the central atom undergoes $sp$ hybridization. So the bond angle is $180 °$ .

In octahedral molecule, the central atom undergoes ${sp}^{3} d^{2}$ hybridization. So the bond angle is $90 °$ .

In trigonal planar molecule, the central atom undergoes ${sp}^{2}$ hybridization. So the bond angle is $120 °$ .

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