Shown in the figure are two point charges +Q and -Q inside the cavity of a spherical shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell. $σ_{1}$ If is the surface charge density on the inner surface and $Q_{1}$ is net charge on it and $σ_{2}$ is the surface charge density on the outer surface and $Q_{2}$ is net charge on it then:

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$σ_{1} \neq 0, Q_{1} = 0 σ_{2} = 0, Q_{2} = 0$

$σ_{1} \neq 0, Q_{1} \neq 0 σ_{2} \neq 0, Q_{2} \neq 0$

$σ_{1} = 0, Q_{1} = 0 σ_{2} = 0, Q_{2} = 0$

$σ_{1} \neq 0, Q_{1} = 0 σ_{2} \neq 0, Q_{2} = 0$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Inside the cavity net charges is zero.

$∴ Q_{1} = 0 and σ_{1} = 0$
There is no effect of point charges $+ Q, - Q$ , and induced charge on the outer surface.

$∴ Q_{2} = 0 and σ_{2} = 0$

Watch 3-min video & get full concept clarity