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Shown in the figure are two point charges +Q and -Q inside the cavity of a shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell.If $σ_{1}$ is the surface charge on the inner surface and Q₁ net charge on it and Q₂ the surface charge on the outer surface and Q₂ net charge on it then

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$σ_{1} \neq 0, Q_{1} \neq 0; σ_{2} \neq 0, Q_{2} \neq 0$

$σ_{1} \neq 0, Q_{1} = 0; σ_{2} \neq 0, Q_{2} = 0$

$σ_{1} \neq 0, Q_{1} = 0; σ_{2} = 0, Q_{2} = 0$

$σ_{1} = 0, Q_{1} = 0; σ_{2} = 0, Q_{2} = 0$

answer is C.

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Detailed Solution

On outer surface there will be no change so $Q_{2} = σ_{2} = 0$
On inner surface total charge will be zero but charge distribution will be there so
$Q_{1} = 0 & σ_{1} \neq 0$

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