Shown in the figure given below are two point charges $+ Q$ and $- Q$ inside the cavity of a spherical shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell. If $σ_{1}$ is the surface charge on the inner surface and $Q_{1}$ net charge on it and $σ_{2}$ the surface charge on the outer surface and $Q_{2}$ net charge on it then

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$σ_{1} \neq 0, Q_{1} \neq 0; σ_{2} \neq 0, Q_{2} \neq 0$

$σ_{1} = 0, Q_{1} = 0; σ_{2} = 0, Q_{2} = 0$

$σ_{1} \neq 0, Q_{1} = 0; σ_{2} = 0, Q_{2} = 0$

$σ_{1} \neq 0, Q_{1} = 0; σ_{2} \neq 0, Q_{2} = 0$

answer is C.

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Detailed Solution

On outer surface there will be no charge.

So $Q_{2} = σ_{2} = 0$

On inner surface total charge will be zero but charge distribution will be there so

$Q_{1} = 0$ and $σ_{1} \neq 0$

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