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${Si}_{2} O_{7}^{6 -}$ anion is obtained when:

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no oxygen of a SiO₄ tetrahedron is shared with another SiO₄ tetrahedron

one oxygen of a SiO₄ tetrahedron is shared with another SiO₄ tetrahedron

two oxygen of a SiO₄ tetrahedron are shared with another SiO₄ tetrahedron

three or all four oxygen of a tetrahedron are shared with other SiO₄ tetrahedron

answer is B.

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Detailed Solution

${Si}_{2} O_{7}^{6 -}$ is obtained when one oxygen of a ${SiO}_{4}^{4 -}$ tetrahedron is shared with another ${SiO}_{4}^{4 -}$ tetrahedron.

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