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Silver and copper voltammeter are connected in parallel with a battery of e.m.f. $12 V$ . In 30 minutes, $1 g m$ of silver and $1.8 g m$ of copper are liberated. The power supplied by the battery is

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24.13 J/s

2.413 J/s

0.2413 J/s

2413 J/s

answer is A.

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Detailed Solution

$m = Z_{q}, ∴ q = \frac{m}{Z}$

Now, $q_{1} = \frac{1}{11.2 x 10^{- 4}} C = 0.89 x 10^{3} C$

$q_{2} = \frac{1.8}{6.6 x 10^{- 4}} C = 2.73 x 10^{3} C$

Total charge,

$q = q_{1} + q_{2} = (0.89 + 2.73) x 10^{3} C = 3.62 x 10^{3} C$

Power supplied by battery, $P = (V q) / t = \frac{12 x 3.62 x 10^{3}}{30 x 60} J / s = 24.13 J / s$

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