Silver nitrate solution when added to a colourless aqueous solution E forms a white precipitate which dissolves in excess of E. If the white precipitate is heated with water it turns black and the supernatant solution gives a white precipitate with acidified barium nitrate solution. Therefore, E is :

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${Na}_{2} {SO}_{4}$

${Na}_{2} S$

${Na}_{2} S_{2} O_{3}$

${Na}_{2} {SO}_{3}$

answer is B.

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Detailed Solution

${Na}_{2} S_{2} O_{3} \overset{{Ag}^{+}}{\to} {Ag}_{2} S_{2} O_{3} ↓ (White) (E) ↓ H_{2} O (Boil) \underset{}{{Na}_{2} S_{2} O_{3}} ↓ Excess$

$\underset{(Black)}{{Ag}_{2} S {Na}_{3}} \underset{(soluble)}{[Ag {(S_{2} O_{3})}_{2}]}$

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