Simplify ${(3-\sqrt{ 3 })}^2$  and choose the option representing the same.

We are given an expression as ${(3-\sqrt{ 3 })}^2$ .
We use the identity ${\left(a-b\right)}^2=a^2-2ab+b^2$ , and expand the given expression.
$\begin{array}{ll}{(3-\sqrt{3})}^2 ={ \left(3\right)}^2-2\times 3\times \sqrt{3}+{\left(\sqrt{3}\right)}^2& \end{array}$ 

$\begin{array}{l}=9-6\sqrt{3}+3\\ \begin{array}{l}=12-6\sqrt{3}\\ =6\left(2-\sqrt{3}\right)\end{array}\end{array}$
So, the simplified form of ${\left(3-\sqrt{ 3 }\right)}^2$  is obtained as  $6\left(2-\sqrt{ 3 }\right)$ .
Hence, the correct option is $6\left(2-\sqrt{ 3 }\right)$.