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Simran was given two bags $A$ and $B$ and full of candies. There were 10 chocolate candies and $5$ full of candies. There were 10 chocolate candies and mango candies in bag A. There were $7$ mango candies in bag A. There were chocolate candies and $3$ chocolate candies and strawberry candies in bag $B$ strawberry candies in bag . She wants to eat chocolate candy. From which bag, should she take the candy, so that the probability of taking a chocolate candy is greater?

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Bag A

Bag B

Cannot be determined

None

answer is B.

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Detailed Solution

According to the question,
The first bag contains 10 chocolate candies and 5 mango candies.
So, the probability of getting a chocolate candy

= 1015

.
The second bag contains 7 chocolate candies and 3 strawberry candies. So, the probability of getting a chocolate candy

= 710

.
On comparing,

⇒ 1015, 710 ⇒ 23, 710 ⇒ 2 × 10 3 × 10, 7 × 3 10 × 3 ⇒ 2030 < 2130

So, the probability of getting a chocolate candy in the Bag B is greater.
The probability of getting a chocolate candy is greater in Bag B.
Hence, option 2 is correct.

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