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Q.

sin2π7+sin4π7+sin8π7=

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a

7/2

b

7/2

c

7/2

d

7/2

answer is A.

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Detailed Solution

Let  s=sin2π7+sin4π7+sin8π7

c=cos2π7+cos4π7+cos8π7

c+is=α+α2+α4.  eq (1)

where  α=cos2π7+isin2π7

is complex 7th root of unity.

cis=α¯+α¯2+α¯4=α6+α5+α3eq(2)

Adding equation (1) and (2) then

2c=α+α2+α4+α6+α5+α3

=α+α2+α3+α4+α5+α6c=12

Also multiplaying eq (1) and (2)  c2+s2=2

s2=2(12)2s=72

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