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Q.

sin5αsin3αcos5α+2cos4α+cos3α=

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a

none

b

cotα

c

tanα/2

d

cotα/2

answer is C.

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Detailed Solution

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=2cos5α+3α2sin5α-3α22cos4α+(cos5α+cos3α) =2cos5α+3α2sin5α-3α22cos4α+(2cos5α+3α2cos5α-3α2)

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