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Q.

Sinxdx=

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a

2[xCosxSinx]+c

b

2[xCosxSinx]+c

c

2[xCosx+Sinx]+c

d

2[xCosx+Sinx]+c

answer is D.

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Detailed Solution

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sinxdx  put x=t2dx=2 t dt
= sint(2tdt)  
= 2t(sint)dt
= 2[t(-cost)-1.(-cost)dt]
= 2[-tcost+sint]+c
= 2[-xcosx+sinx]+c

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