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$s i n 0 ° + c o s 30 ° - t a n 45 ° + c o \sec 60 ° =$

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7 \sqrt{3}

\frac{1 - \sqrt{3}}{2 \sqrt{3}}

\frac{7 + 2 \sqrt{3}}{2 \sqrt{3}}

\frac{7 - 2 \sqrt{3}}{2 \sqrt{3}}

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detailed solution

Correct option is D

$s i n 0 ° + c o s 30 ° - t a n 5 ° + c o \sec 60 °$

$= 0 ° + \frac{\sqrt{3}}{2} - 1 + \frac{2}{\sqrt{3}}$

$= \frac{\sqrt{3}}{2} + \frac{2}{\sqrt{3}} - 1$

$= \frac{(\sqrt{3}) (\sqrt{3}) + 2 (2) - 2 (\sqrt{3})}{2 \sqrt{3}}$

$= \frac{3 + 4 - 2 \sqrt{3}}{2 \sqrt{3}}$

$= \frac{7 - 2 \sqrt{3}}{2 \sqrt{3}}$

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sin0°+cos30°−tan45°+cosec60°=

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$s i n 0 ° + c o s 30 ° - t a n 45 ° + c o \sec 60 ° =$