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Q.

Sin2270 + Sin2870 + Sin2330 =

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a

2

b

1

c

12

d

32

answer is C.

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Detailed Solution

  Sin2270 + Sin2870 + Sin2330 =1-cos2870+sin2270+1-cos2(330)2 =1-cos2870-sin2270+12-12 cos660 =1-cos1140 cos600+12-12 cos660 =1-cos1800-660 12+12-12 cos660 =1+12+12 cos660-12 cos660 =32

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