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sin24°+sin32°+sin204°+sin212°=

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By Expert Faculty of Sri Chaitanya
a
1
b
1
c
0
d
2
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detailed solution

Correct option is C

sin24°+sin32°+sin204°+sin212°

=sin24°+sin32°+sin(180°+24°)+sin(180°+32°)

=sin24°+sin32°sin24°sin32°

=0


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