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Q.

Sin2500 + Sin2700 + Sin21700=

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a

2

b

1

c

12

d

32

answer is C.

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Detailed Solution

  sin2500 + sin2700 + sin21700 =1-cos2700+sin2500+sin2(1800-100) =1-cos2700-sin2500+sin2100 =1-cos1200 cos200+1-cos2002 =1+12cos20+12-12cos200 =1+12=32

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