∫sin2x+2tanxcos6x+6cos2x+4dx=1αlnβ+γcos4x+δcos6x+c,, then match the below Column-I Column-IIa.αp.1b.βq.12c.γr.4d.δs.6

∫2(cos x+1cos x)cos6x+6cos2x+4dx, cosx=t

∫sin2x+2tanxcos6x+6cos2x+4dx=1αlnβ+γcos4x+δcos6x+c,, then match the below Column-I Column-IIa.αp.1b.βq.12c.γr.4d.δs.6

∫2(cos x+1cos x)cos6x+6cos2x+4dx, cosx=t

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$\int \frac{\sin 2 x + 2 \tan x}{\cos^{6} x + 6 \cos^{2} x + 4} d x = \frac{1}{α} \ln |β + \frac{γ}{\cos^{4} x} + \frac{δ}{\cos^{6} x}| + c,$ , then match the below
Column-I Column-II
a. $α$ p. 1
b. $β$ q. 12
c. $γ$ r. 4
d. $δ$ s. 6

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$(a, q), (b, p), (c, s), (d, r)$

$(a, p), (b, q), (c, s), (d, r)$

$(a, q), (b, p), (c, r), (d, s)$

$(a, p), (b, q), (c, r), (d, s)$

answer is C.

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$\int \frac{2 (\cos x + \frac{1}{\cos x})}{\cos^{6} x + 6 \cos^{2} x + 4} d x, \cos x = t$

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∫sin2x+2tanxcos6x+6cos2x+4dx=1αlnβ+γcos4x+δcos6x+c,, then match the below Column-I Column-IIa.αp.1b.βq.12c.γr.4d.δs.6

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$\int \frac{\sin 2 x + 2 \tan x}{\cos^{6} x + 6 \cos^{2} x + 4} d x = \frac{1}{α} \ln |β + \frac{γ}{\cos^{4} x} + \frac{δ}{\cos^{6} x}| + c,$ , then match the below
Column-I Column-II
a. $α$ p. 1
b. $β$ q. 12
c. $γ$ r. 4
d. $δ$ s. 6