$(\sin 30° + \cos 30°) - (\sin 60° + \cos 60°) \mathrm{is} \mathrm{equal} \mathrm{to}$

$\mathrm{As} \mathrm{we} \mathrm{have} \mathrm{to} \mathrm{find} \mathrm{the} \mathrm{value} \mathrm{of} (\sin 30° + \cos 30°) - (\sin 60° + \cos 60°).$

$\mathrm{so} \mathrm{using} \mathrm{the} \mathrm{identities} \mathrm{for} \mathrm{trigonometry},$

$\sin 30° = \frac{1}{2}$

$\cos 30°= \frac{\sqrt{3}}{2}$

$\sin 60° = \frac{\sqrt{3}}{2}$

$\cos 60° = \frac{1}{2}$

Therefore, $(\sin 30° + \cos 30°) - (\sin 60° + \cos 60°)=(\frac{1}{2}+\frac{\sqrt{3}}{2}) - ( \frac{\sqrt{3}}{2}+\frac{1}{2})$

$=0$