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Q.

sin(n+1)A+2sinnA+sin(n1)Acos(n-1)Acos(n+1)A=

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a

tan A2

b

cotA2 

c

tan A

d

cot A

answer is B.

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Detailed Solution

sin(n+1)A+2sinnA+sin(n1)Acos(n1)Acos(n+1)A =sin(n+1)A+sin(n1)A+2sinnAcos(n1)Acos(n+1)A= =2sinnAcosA+2sinnA2sinAsinnA=1+cosAsinA=cotA2

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