Q.

sinθ+sin(θ+120)sin120θ=

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a

sinθ

b

1

c

sinθ

d

0

answer is A.

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Detailed Solution

sinθ+120=sinθcos120+cosθsin120

=sinθ2+3cosθ2

sin120θ=sin120cosθcos120sinθ

=3cosθ2+sinθ2

sinθ+sinθ+120sin120θ

=sinθsinθ2+3cosθ23cosθ2+sinθ2=sinθsinθ2+3cosθ23cosθ2sinθ2=0

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