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Q.

sinx-acosx-bdx=Alogsecx-b+Bx+C then the value of B is

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a

cosb-a

b

sinb-a

c

cosb+a

d

sinb+a

answer is B.

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Detailed Solution

sin(xa)cos(xb)=sin(xb+(ba))cos(xb)=tan(xb)cos(ba)+sin(ba)sin(xa)cos(xb)dx=cos(ba)tan(xb)dx+sin(ba)dx=cos(b a) log|sec(xb)|+sin(ba)x+C

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