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Q.

Siphon is in action in the given figure. The liquid flowing through the siphon has a density of 1.5 gm/cc. If the pressure difference between points B and C is x Pascal then find x.

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Detailed Solution

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If P_B is the pressure at B
$P_{0} = P_{B} + {ρgh}_{1} + \frac{1}{2} {ρV}^{2}$
If P_C is the pressure at C
$\begin{array}{l} P_{0} = P_{C} + {ρgh}_{2} + \frac{1}{2} {ρV}^{2} \\ P_{B} - P_{C} = (P_{0} - {ρgh}_{1}) - (P_{0} - {ρgh}_{2}) \\ {ρgh}_{2} - ρgh = ρg (50 - 20) = 1.5 \times 980 \times 30 = 44100 dyne / {cm}^{2} \end{array}$

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