six digit numbers divisible by 3 is formed using 0, 1, 2, 3, 4 and 5 without repetetion. Total number of such numbers are

The given digits are $0,1,2,3,4,5$

The number of six digit numbers divisible by 3 formed using $0,1,2,3,4,5$  : 

Since zero included in the number, first digit must be placed any one of the numbers $1,2,3,4,5$, this can be done in 5 ways

The remaining five digits can be filled with the remaining five digits in $5!$ ways. 

Therefore, the number of six digit numbers, which are divisible by 3 formed by the digits $0,1,2,3,4,5$ without repetition is $5\left(5!\right)=\boxed{600}$