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Q.

Six faces of a die are marked with numbers 1, -1, 0, -2, 2, 3 and the die is thrown thrice. The probability that the sum of the numbers thrown is six is

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a

$\frac{18}{216}$

b

$\frac{3}{216}$

c

$\frac{10}{216}$

d

$\frac{6}{216}$

answer is C.

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Detailed Solution

Sum 6 on 3 dices = (3,3,0) → 3 ways = (2,2,2) →1 way (1,2,3) →3!=6ways
Total = 10ways

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Six faces of a die are marked with numbers 1, -1, 0, -2, 2, 3 and the die is thrown thrice. The probability that the sum of the numbers thrown is six is