Six faces of a die are marked with numbers 1, –1, 0, –2, 2, 3 and the die is thrown thrice. The probability that the sum of the numbers thrown is six, is

A  die are marked with numbers 1, –1, 0, –2, 2, 3 . The die is thrown thrice.

$n\left(S\right)=6^3=216$

$\mathrm{E}=\mathrm{event} \mathrm{of} \mathrm{getting} \mathrm{a} \mathrm{sum} 6$

$\mathrm{E}=\left(2,2,2\right).....1 \mathrm{way},\left(3,3,0\right).....3 \mathrm{ways},\left(1,2,3\right) ....6 \mathrm{ways}$

$\Rightarrow \mathrm{n}\left(\mathrm{E}\right)=10$

$P\left(E\right)=\frac{10}{216}$