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Q.

Six identical charges each +Q are at the vertices of a regular hexagon of side “L”.  The electric potential at the center of the hexagon is ‘V’. If one of the charges is reversed in sign, the potential now at the center of the hexagon will be

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a

V/2       

b

5V/6  

c

3V/4

d

2V/3

answer is B.

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Detailed Solution

V=K.6qd

2nd case, V1=k5qd−qd

⇒V1=k.4qd

V1=2V3

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