Six identical conducting rods are connected as shown in figure. In steady state temperature of point a is fixed at 100°C and temperature of point e is fixed at -80°C. Match the following two columns.

COLUMN – I COLUMN – II
A) Temperature of b P) 10°C
B) Temperature of c Q) 40°C
C) Temperature of f R) -20°C
D) Temperature of d S) 80°C

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$A \to Q, B \to P, C \to S, D \to R$

$A \to R, B \to S, C \to P, D \to P$

$A \to P R, B \to S, C \to Q, D \to S$

$A \to Q, B \to P, C \to P, D \to R$

answer is D.

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Detailed Solution

According to temperature deviser rule $T_{A} - T_{B} = \frac{1}{3} (T_{a} - T_{c})$
$100 - T_{b} = \frac{1}{3} (100 - (- 80)) \Rightarrow T_{b} = 40^{0} C$
$T_{d} - T_{c} = \frac{1}{3} (T_{a} - T_{c}) = T_{d} = - 28 C$

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	COLUMN – I		COLUMN – II
A)	Temperature of b	P)	10°C
B)	Temperature of c	Q)	40°C
C)	Temperature of f	R)	-20°C
D)	Temperature of d	S)	80°C