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Six moles of equimolar mixture of diborane and oxygen taken in a closed rigid container undergoes combustion reaction. What is change in the entropy of surrounding at 300 K, if it is assumed that all the heat released is dissipated into the surrounding? Report the value in kJ/Kelvin. Given that one mole of diborane on combustion releases 2009.96 k J/mol at constant pressure. R= 8.3 J $m o l^{- 1} K^{- 1} .$

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answer is 6.66.

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Detailed Solution

$B_{2} H_{6} + 3 O_{2} \to B_{2} O_{3} + H_{2} O$

Change in enthalpy= change in internal energy + (–3) RT
Oxygen is the limiting reagent.

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