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Q.

Six years hence, a man's age will be three times the age of his son and three years ago he was nine times as old as his son. The present age of the man is


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a

28years

b

30years

c

32years

d

34years  

answer is B.

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Detailed Solution

It is given  a man's age will be three times the age of his son and three years ago he was nine times as old as his son.
Let the present age of man be years and the present age of son be y years,
After six years,
Man's age  = (x+6) years
Son's age  = (y+6) years
According to the condition,
 x+6=3(y+6)
 x-3y=12  x=12+3y ...(1) Three years ago,
Man's   age = (x-3) years
Son's   age = (y-3) years
According to the condition
 x-3=9(y-3)  x-9y=-24 ...(2) Put the value of in (2),  12+3y-9y=-24
 y=6 Put the value of y in (1),
 x-3×6=12
 x=30 So, Man's age =  30 years.
Therefore, the present age of man is 30 years.
Hence, correct option is 2.
 
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