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Size of a tile is $9$ inches by $9$ inches. How many number of tiles needed to cover a floor of $12$ feet by $18$ feet?

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384

32

24

216

answer is A.

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Detailed Solution

Given, size of a tile is

9

inches by

9

inches.
Area of a square is

sid e^{2}

.
Area of a tile = Area of a square =

sid e^{2} .

Area of a tile =

9 inches \times 9 inches

Area of a rectangle is (length)×(breadth).

\Rightarrow

Area of the floor = (length)

\times

(breadth).

\Rightarrow

Area of the floor =

12 feet \times 18 feet

We know that 1 feet = 12 inches.

\Rightarrow

Area of the floor =

12 \times 12 inches \times 18 \times 12 inches

Number of tiles

= \frac{Area Of Floor}{Area Of Tile}

\Rightarrow

Number of tiles

= \frac{12 \times 12 \times 18 \times 12}{9 \times 9}

\Rightarrow

Number of tiles

= 384

Hence, option 1 is correct.

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Size of a tile is 9 inches by 9 inches. How many number of tiles needed to cover a floor of 12 feet by 18 feet?

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Size of a tile is $9$ inches by $9$ inches. How many number of tiles needed to cover a floor of $12$ feet by $18$ feet?