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Q.

Small conducting square loop of side length d=10 cm, is at h height above the boundary of a region of uniform magnetic field. B0=1T (into the plane of the paper in figure). The mass of the square loop is m = 100 gram and resistance  R=0.1Ω. The loop is dropped from such position and after some time it enters the magnetic field region. Find the height ‘h’ in metre so that velocity of the loop will remain constant during the time interval the loop will be entering into the magnetic field region. (g=10m/s2)

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answer is 5.

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Detailed Solution

v2=2gh  and  i=vBIR

mgv=v2B2I2R

mgRB2I2=vm2g2R2B4I4=2gh=m2gR22B4I4=1×10100×1×100×100100×2×1=5m

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