$S n C l_{2} \cdot 2 H_{2} O$ readily loses one molecule of water at $80^{\circ} C$ because :

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one water molecule is bonded to ${SnCl}_{2}$ by coordinate covalent bond and the other is held by ion dipole attractive forces to central metal ion.

both the water molecules are bonded to pyramidal ${SnCl}_{2}$ by hydrogen bonds

one water molecule has coordinated a lone pair of electron to ${SnCl}_{2}$ and the other is hydrogen bonded to coordinated w~ ter molecule.

both the water molecules are coordinated to lone pairs of electrons on pyramidal ${SnCl}_{2}$ .

answer is A.

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Detailed Solution

The water molecule is so prevalent that it is advisable to merely commit to memory that it is a bent molecule. Oxygen needs 2 more electrons from 2 hydrogen atoms in order to complete its octet because it has 6 valence electrons. Additionally, two pairs of free electrons that are not connected to any other atoms are left.

$S n C l_{2} \cdot 2 H_{2} O$ easily loses one water molecule.

One water molecule has coordinated a lone pair at because at 80 °C.

$S n C l_{2}$ , and hydrogen is the other source of electrons.

bonded to coordinated water molecule.

Hence correct option A

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